If it's not what You are looking for type in the equation solver your own equation and let us solve it.
n^2+25n+12=0
a = 1; b = 25; c = +12;
Δ = b2-4ac
Δ = 252-4·1·12
Δ = 577
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(25)-\sqrt{577}}{2*1}=\frac{-25-\sqrt{577}}{2} $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(25)+\sqrt{577}}{2*1}=\frac{-25+\sqrt{577}}{2} $
| 4(-2m+6)=20 | | t-17=7 | | 2/3(x-10)=10 | | 56+(p+32)+(p-14)=180 | | 23(x-10)=10 | | –3j+8j=5j | | 35x+55x=180 | | -19+9p-13=-4p+20 | | 7/3x-1/2=x+7/2 | | -23+3x=-2(1-3x) | | 4h−14=2 | | 0.30=18x | | 91+(p+29)+(p+30)=180 | | 2(x+6)=12x= | | 3=2t−13 | | 3t+-7=17 | | 5w+17=-11+19w | | 14.3=3u-24.1 | | X^2-10x+x^2+14x-7=0 | | 5x-3x+7=-1x= | | 6-12=4a-20 | | -27=8t-11 | | 3.5x=130+10x* | | 4z-3z+8=180 | | 3x−10=9 | | 38+25z+46z=180 | | 5•4x-12=28 | | 5=2x+2x=6 | | -2/3h=- | | -27=8t—11 | | x*0.025=1 | | Y=6+7+x |